Question

Preciso do cálculo por favorr

Answer 1

$x = ( { {2}^{2} })^{3} = {4}^{3 } = 64 \\ y = { {2}^{2} }^{3} = {2}^{6} = 128 \\ z = { {2}^{3} }^{2} = {2}^{6} = 128 \\ \frac{x.y}{z} = \frac{64.128}{128} = \frac{8192}{128} = 64$

x=64

y=128

z=128