preciso desta resposta urgente 1/6.(4x-12)=6x/5
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![\frac{1}{6} (4x-12)= \frac{6x}{5} \frac{1}{6} (4x-12)= \frac{6x}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B6%7D+%284x-12%29%3D+%5Cfrac%7B6x%7D%7B5%7D+)
![\frac{4x-12}{6} = \frac{6x}{5} \frac{4x-12}{6} = \frac{6x}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B4x-12%7D%7B6%7D+%3D+%5Cfrac%7B6x%7D%7B5%7D+)
![20(x-3)=36x 20(x-3)=36x](https://tex.z-dn.net/?f=20%28x-3%29%3D36x)
![20x -60 =63x 20x -60 =63x](https://tex.z-dn.net/?f=20x+-60+%3D63x)
![-60 = 36x -20x -60 = 36x -20x](https://tex.z-dn.net/?f=-60+%3D+36x+-20x)
![-60 = 16x -60 = 16x](https://tex.z-dn.net/?f=-60+%3D+16x)
![x = - \frac{60^{:4}}{16^{:4}} = \boxed{\boxed{- \frac{15}{4} }} x = - \frac{60^{:4}}{16^{:4}} = \boxed{\boxed{- \frac{15}{4} }}](https://tex.z-dn.net/?f=x+%3D+-+%5Cfrac%7B60%5E%7B%3A4%7D%7D%7B16%5E%7B%3A4%7D%7D+%3D+%5Cboxed%7B%5Cboxed%7B-+%5Cfrac%7B15%7D%7B4%7D+%7D%7D)
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