Question

PRECISO DESSE EXERCICOS RECUPERAÇÃO

Answer 1

3a) $5^{-9} . 5^{16} = 5^{-9+16} = 5^{7}$

3b) $( 125^{2} . (25)^{-4} .5^7)^2=( (5^{3} )^{2} . ( 5^{2} )^{-4} .5^7)^4=(5^6. 5^{-8} .5^7)^2= (5^{5} )^4= 5^{20}$

4a) $(2^{13}.8^3. 16^{-4} . 64^{-2} )^4=(2^{13}.(2^{3} )^3. (2^4)^{-4} . ( 2^{6}) ^{-2} )^4=( 2^{13} .2^9. 2^{-16} . 2^{-12)^2} \\ \\ = (2^{-6})^2 = 2^{-12}$

4b) 
$\frac{3^4. 27^{-2}. 243^{-1} }{81^2. 3^{-8} } = \frac{3^4. (3^{3}) ^{-2}. (3^{5} )^{-1} }{(3^{3} )^2. 3^{-8} } = \frac{3^4. 3^{-6}. (3)^{-5} }{3^6. 3^{-8} } = \frac{ 3^{-7} }{ 3^{-2} } = 3^{-7+2} = 3^{-5}$

2a) $7^3 =7.7.7=343$

2b) $2^8=2.2.2.2.2.2.2.2=256$

2c)$5^3 = 5.5.5 = 125$

2d)$( \frac{6}{5} )^{-2} = ( \frac{5}{6} )^{2}= \frac{5^2}{6^2} = \frac{25}{36}$

2e)$2^{-6} = ( \frac{1}{2} )^{6} = \frac{1^6}{2^6} = \frac{1}{64}$

2f)$0^{436} =0$

2g)$1^{2950} =1$