Question

Preciso dessa urgente!

Answer 1

$\boxed{ \underbrace{(8 {x }^{5} y + 22 {x}^{4} {y}^{2} + 11 {x}^{3} {y}^{3} - 6 {x}^{2} {y}^{4} ) }}$

Explicação passo-a-passo:

Utilizando a propriedade distributiva temos:

$(4 {x }^{3} + 5 {x}^{2} y - 2x {y}^{2}) \times (2 {x}^{2} y + 3x {y}^{2} )$

$(8 {x }^{5} y + 10 {x}^{4} {y}^{2} - 4 {x}^{3} {y}^{3} + 12 {x}^{4} {y}^{2} + 15 {x}^{3} {y}^{3} - 6 {x}^{2} {y}^{4} )$

$\boxed{ \underbrace{(8 {x }^{5} y + 22 {x}^{4} {y}^{2} + 11 {x}^{3} {y}^{3} - 6 {x}^{2} {y}^{4} ) }}$

Answer 2

Oie, Td Bom?!

$= (4x {}^{3} + 5x {}^{2} y - 2xy {}^{2} ) \: . \: (2x {}^{2} y + 3xy {}^{2} )$

$= 4x {}^{3} \: . \: (2x {}^{2} y + 3xy {}^{2} ) + 5x {}^{2}y \: . \: (2x {}^{2} y + 3xy {}^{2} ) - 2xy {}^{2} \: . \: (2x {}^{2} y + 3xy {}^{2})$

$= 8x {}^{5} y + 12x {}^{4}y {}^{2} + 10x {}^{4} y {}^{2} + 15x {}^{3} y {}^{3} - 4x {}^{3} y {}^{3} - 6x {}^{2} y {}^{4}$

$= 8x {}^{5} y + 22x {}^{4} y {}^{2} + 11x {}^{3} y {}^{3} - 6x {}^{2} y {}^{4}$

Att. Makaveli1996