Question

Preciso de ajuda nesse cáculo(Forma de Baskhara) -x/2 + 6x -5 = 0

Answer 1

b^2-4×a×c

6^2-4×(-1)×(-5)

36-20

delta= 16

$\frac{ - 6 + \sqrt{16} }{2 \times ( - 1) } = \frac{ - 2}{ - 2} = 1$

$\frac{ - 6 - \sqrt{16} }{2 \times ( - 1)} = \frac{ - 10}{ - 2} = 5$

x=1

x=5