Question

preciso de ajuda me ajudem por favor

Answer 1

a) Utilizando a formulação da tangente:

$tg(\alpha)=\frac{cateto\;oposto}{cateto\;adjacente}\\\\tg(30^\circ)=\frac{x}{12}\\\\\frac{\sqrt{3}}{3}= \frac{x}{12}\\ \\3x=12\sqrt{3}\\\\x = \frac{12\sqrt{3}}{3}\\ \\x = 4\sqrt{3}$

b) Utilizando a formulação do seno:

$sen(\alpha)=\frac{cateto\;oposto}{hipotenusa}\\\\sen(45^\circ)=\frac{20}{x}\\\\\frac{\sqrt{2}}{2}= \frac{20}{x}\\ \\\sqrt{2}x=2*20\\\\x = \frac{40}{\sqrt{2}}\\ \\x=\frac{40}{\sqrt{2}}.\frac{\sqrt{2}}{\sqrt{2}}\\\\x=\frac{40\sqrt{2}}{\sqrt{2}^2}\\\\x=\frac{40\sqrt{2}}{2}\\\\x = 20\sqrt{2}$