Question

Preciso de ajuda com essas duas questões urgentemente!

Answer 1

.
Ola Iaml

A)

log4(64) = log(64)/log(4) = log(2^6)/2log(2) = 6log(2)/2log(2) = 3

log9(3) = log(3)/2log(3) = 1/2 

log3(81) = log3(3^4) = 4 

log4(4) = 1

1 + 1/2 = 3/2 (B)

B)

4^(2 - log16(9) =

16  * 4^- log16(9)

-log16(9) = -log(9)/log(16) = -2log(3)/4log(2) = -log(3)/log(4) 

= log(1/3)/log(4) 

4^- log16(9) = 4^(log(1/3)/log(4) = 1/3

16 * 1/3 = 16/3 (E)