Question

preciso da equacao do 2 grau (ax²+bx+c=0) desta equação (n precisa bhaskara)

$(x - 4)^{2} + \frac{15 - x}{3} = 27$


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Answer 1

Resposta:

$(x - 4)^{2} + \frac{15 - x}{3} = 27\\\\\frac{3(x - 4)^{2}+15-x}{3} =27\\\\{3(x^{2}-8x+16)+15-x=81$

$3x^{2}-24x+48+15-x=81\\3x^{2}-25x-18=0$

Answer 2

Resposta:

Explicação passo-a-passo:

(x - 4)^{2} + \frac{15 - x}{3} = 27\\\\\frac{3(x - 4)^{2}+15-x}{3} =27\\\\{3(x^{2}-8x+16)+15-x=81

3x^{2}-24x+48+15-x=81\\3x^{2}-25x-18=0