Question

PRECISO DA 5 B, PUFAVO

Answer 1

Explicação passo-a-passo:

$\sqrt[3]{4} \times \sqrt{ {2}^{x} } = \sqrt[6]{2}$

$\sqrt[6]{ {4}^{2} } \sqrt[6]{ {2}^{3x} } = \sqrt[6]{2}$

$\sqrt[6]{ {4}^{2} } \sqrt[6]{ {2}^{3x} } = {2}^{ \frac{1}{6} }$

$\sqrt[6]{ {4}^{2} \times {2}^{3x} } = {2}^{ \frac{1}{6} }$

$\sqrt[6]{ {2}^{4} \times {2}^{3x} } = {2}^{ \frac{1}{6} }$

$\sqrt[6]{ {2}^{3x + 4} } = {2}^{ \frac{1}{6} }$

${2}^{ \frac{3x + 4}{6} } = {2}^{ \frac{1}{6} }$

$\frac{3x + 4}{6} = \frac{1}{6}$

$3x + 4 = 1$

$3x = 1 - 4$

$3x = - 3$

$x = - 1$