Question

PRA AGORA! EU IMPLORO!

Answer 1

x^2-4x+3=0
delta=b^2-4ac
delta=(-4)^2-4.1.3
delta=16-12
delta=4
x=-b-/+ raiz de delta/2a
x=-(-4)-2/2.1
x=4-2/2
x=2/2
x=1
x=-(-4)+2/2.1
x=4+2/2
x=6/2
x=3
S={1,3}

Answer 2

x² - 4x + 3

Δ=-4²-4*1*3
Δ=16-12
Δ=4

x = (-b+-√Δ)/2a
x = (-(-4)+-√4)/2*1
x = (4+-2)/2

x' = (4+2)/2
x' = 6/2
x' = 3

x'' = (4-2)/2
x'' = 2/2
x'' = 1


S (1,3)