Question

Potenciação 

Gabarito da D

Answer 1

$4^{16}*5^{25}= \alpha10^{n}\\2^{32}*5^{25}=\alpha10^{n}\\2^{25}*2^{7}*5^{25}=\alpha10^{n}\\(2*5)^{25}*128=\alpha10^{n}\\128*10^{25}=\alpha10^{n}$
Como 1≤ α <10, temos:
$1,28*10^{2}*10^{25}=\alpha10^{n}\\1,28*10^{27}=\alpha10^{n}\\ \alpha =1,28\\n=27$