Question

Potenciação e radiciação do 9º ano, alguém faz essa questão pra mim?

Answer 1

$\frac{ (x^{-2}) ^{2} + x^{ \frac{1}{2} } . x^{-3} }{ x^{-5} }$

$\frac{ (x^{-4}) + x^{ \frac{1}{2}-3 }}{ x^{-5} }$

$\frac{ (x^{-4}) + x^{ -\frac{5}{2}}}{ x^{- 5 } }$

$x^{-4+5} + x^{- \frac{5}{2} +5}$

$x + x^{\frac{5}{2}}$

$x + \sqrt{ x^{5} }$

$x + x^{2} \sqrt{ x } = x.(x. \sqrt{x} +1)$

Answer 2

 Olá Bruvares,
boa noite!

$\left[(x^{-2})^2+x^{\frac{1}{2}}\cdot\,x^{-3}\right]\div\,x^{-5}=\\\\\frac{\left[x^{-4}+\sqrt[2]{x}\cdot\,x^{-3}\right]}{x^{-5}}=\\\\\frac{\left[x^{-4}(x^0+\sqrt{x}\cdot\,x^1)\right]}{x^{-4}\cdot\,x^{-1}}=\\\\(1+\sqrt{x}\cdot\,x)\div\frac{1}{x}=\\\\(1+\sqrt{x}\cdot\,x)\cdot\,x=\\\\4(1+\sqrt{4}\cdot4)=\\\\4(1+8)=\\\\\boxed{36}$