Question

potência de um número real com expoente inteiro negativo !
$6 { - }^{2}$
$( - 7 ) { - }^{2}$
$( - 11){-}^{2}$
$4{-}^{3}$
$( - 3) { - }^{3}$
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Answer 1

Olá, tudo bem?

$6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}\checkmark\\\\\\(-7)^{-2}=\dfrac{1}{(-7)^2}=\dfrac{1}{(-1)^2}\cdot\dfrac{1}{7^2}=\dfrac{1}{1}\cdot\dfrac{1}{49}=\dfrac{1}{49}\checkmark\\\\\\(-11)^{-2}=\dfrac{1}{(-11)^2}=\dfrac{1}{121}\checkmark\\\\\\4^{-3}=\dfrac{1}{4^3}=\dfrac{1}{64}\checkmark\\\\\\(-3)^{-3}=\dfrac{1}{(-3)^3}=\dfrac{1}{-27}\checkmark$

É isso!! :)