Question

Por favor preciso de ajuda!
Com resolução.

Answer 1

$\int\ \dfrac{x^5+2x^2-1}{x4} \, dx = \int\(x+2x^{-2}-x^{-4}) \, dx = \\ \\ = \dfrac{x^2}{2} +\dfrac{2x^{-2+1}}{-2+1} +\dfrac{x^{-4+1}}{-4+1} = \\ \\ = \dfrac{x^2}{2} - \dfrac{2}{x} -\dfrac{3}{x^3} +C$

$\int\ (x^{\frac{-1}{2}} -3x^{ \frac{7}{5}} + \dfrac{1}{9}) \, dx = \\ \\ = \dfrac{(x^{\frac{-1}{2}+1})}{ \dfrac{-1}{2} +1} - \dfrac{(3x^{\frac{7}{5}+1})}{ \dfrac{7}{5} +1} + \dfrac{1}{9}x = \dfrac{(x^{\frac{1}{2}})}{ \dfrac{1}{2}} - \dfrac{(3x^{\frac{12}{5}})}{ \dfrac{12}{5}} + \dfrac{1}{9}x = \\ \\ \\ = 2(x^{\frac{1}{2}})} - \dfrac{15}{12}(x^{\frac{12}{5}})} + \dfrac{1}{9}x + C$

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Obrigado pela oportunidade. 
Boa sorte, bons estudos.
SSRC - 2015 
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