Question

Por favor,preciso de ajuda!!​

Answer 1

Resposta:

a) y=8

b) x=20/3 (vinte terços)

c) x=11/4 (onze quartos)

Answer 2

Explicação passo a passo:

a)

$\sf \dfrac{y}{4} + 1 = 7 - \dfrac{y}{2}$

mmc(4,2) = 4

$\sf 4\div4*(y) + 4*(1) = 4*(7) - 4\div2*(y)$

$\sf y + 4 = 28 - 2y$

$\sf y + 2y = 28 - 4$

$\sf 3y = 24$

$\sf y = \dfrac{24}{3}$

$\pink{\sf y = 8}$

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b)

$\sf \dfrac{x-2}{4} + \dfrac{x-3}{2} = \dfrac{x-1}{3} + \dfrac{x}{6}$

mmc(4,2,3,6) = 12

$\footnotesize{\sf 12\div4*(x-2) + 12\div2*(x-3) = 12\div3*(x-1) + 12\div6*(x)}$

$\sf 3x - 6 + 6x - 18 = 4x - 4 + 2x$

$\sf 9x - 24 = 6x - 4$

$\sf 9x - 6x = - 4 + 24$

$\sf 3x = 20$

$\pink{\sf x = \dfrac{20}{3}}$

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c)

$\sf \dfrac{2(x-1)}{3} - \dfrac{3(x+1}{2} = - \dfrac{(x+2)}{6}$

$\sf \dfrac{2x-2}{3} - \dfrac{3x+3}{2} = - \dfrac{x+2}{6}$

mmc(3,2,6) = 6

$\footnotesize{\sf 6\div3*(2x-2) + 6\div2*(-(3x+3)) = 6\div6*(-(x+ 2))}$

$\footnotesize{\sf 6\div3*(2x-2) + 6\div2*(-3x-3) = 6\div6*(-x- 2)}$

$\sf 4x - 4 - 9x - 9 = - x - 2$

$\sf - 5x - 13 = - x - 2$

$\sf - 5x + x = - 2 + 13$

$\sf - 4x = 11~~~~*(-1)$

$\sf 4x = - 11$

$\pink{\sf x = - \dfrac{11}{4}}$