Question

Por favor me expliquem a resolução detalhadamente...

Answer 1

$[ \sqrt{ ( \frac{1}{6} )^{-3} .0,666...} + \sqrt{ ( \frac{5}{7} )^{0}- \frac{1}{1,333...} } ]^{- \frac{1}{2} }$

$[ \sqrt{ ( 6 )^{3} . \frac{6}{9} } + \sqrt{ 1- \frac{1}{ \frac{13-1}{9} } } ]^{- \frac{1}{2} }$

$[ \sqrt{ 2^{3} . 3^{3} . \frac{6}{ 3^{2} } } + \sqrt{ 1- \frac{1}{ \frac{12}{9} } } ]^{- \frac{1}{2} }$

$[ \sqrt{ 2^{3} . 3. 6 } } + \sqrt{ 1- \frac{9}{12} } } ]^{- \frac{1}{2} }$

$[ \sqrt{ 2^{4} . 3^{2} } } + \sqrt{ \frac{12-9}{12} } } ]^{- \frac{1}{2} }$

$[ 2^{2}.3 + \sqrt{ \frac{3}{12} } } ]^{- \frac{1}{2} }$

$[ 12 + \sqrt{ \frac{1}{4} } } ]^{- \frac{1}{2} }$

$[12 + \frac{1}{2} ]^{- \frac{1}{2} }$

$[ \frac{24+1}{2} ]^{- \frac{1}{2} }$

$[ \frac{25}{2} ]^{- \frac{1}{2} }$

$[ \frac{2}{25} ]^{ \frac{1}{2} }$

$\sqrt{\frac{2}{25}}$

$\frac{ \sqrt{2} }{ \sqrt{25} }$

$\frac{ \sqrt{2} }{ 5 }$