Question

Por favor me ajudem !

{72-20+[15-(3+1)]}




(30x5+4)-12÷6+8)






50-[5+(8-3)x2]

Answer 1

$\{72-20+[15-(3+1)]\}=\{52+[15-4]\}$

$\{72-20+[15-(3+1)]\}=\{52+11\}$

$\{72-20+[15-(3+1)]\}=63$


$(30\cdot5+4)-12\div6+8=(150+4)-2+8$

$(30\cdot5+4)-12\div6+8=154+6$

$(30\cdot5+4)-12\div6+8=160$


$50-[5+(8-3)\times2]=50-[5+5\times2]$

$50-[5+(8-3)\times2]=50-[5+10]$

$50-[5+(8-3)\times2]=50-15$

$50-[5+(8-3)\times2]=35$

Answer 2

A)  {72-20 + [15 - (4)]}
{ 52 +11}
{ 63}

B) ( 150 + 4) -2 + 8)
(154 - 2 + 8)
(152 + 8)
(160)

C) 50- [ 5 + (5) . 2]
50 -  [ 5 + 10]
50 - 15
35