Question

Por favor me ajudem!!!!!!!!!

Answer 1

$x + \frac{19}{3} + \frac{23}{3} + 6 = 30$
$3x + 19 + 23 + 18 = 90$
$3x = 30$
$x = 10$
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$10 + \frac{17}{3} + z + 9 = 30$
$30 + 17 + 3z + 27 = 90$
$3z = 16$
$z = \frac{16}{3}$
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$\frac{17}{3} + y + 7 + 9 = 30$
$17 + 3y + 21 + 27 = 90$
$3y = 25$
$y = \frac{25}{3}$
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$\frac{19}{3} + \frac{25}{3} + 8 + w = 30$
$19 + 25 + 32 + 3w = 90$
$3w = 14$
$w = \frac{14}{3}$
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$\frac{23}{3} + 7 + \frac{20}{3} + a = 30$
$23 + 21 + 20 + 3a = 90$
$3a = 26$
$a = \frac{26}{3}$
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$\frac{25}{3} + 10 + \frac{20}{3} + b = 30$

$25 + 30 + 20 + 3b = 90$
$3b = 15$

$b = 5$

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$9 + 6 + c + 5 = 30$
$c = 10$