Question

Por favor me ajudaa ​

Answer 1

Resposta:

$sen(x)=\frac{catetooposto}{hipotenusa}\\cos(x)= \frac{cateto adjacente}{hipotenusa}\\\\a) sen(38)=\frac{a}{20}\\0,6=\frac{a}{20}\\a=0,6.20\\a= 12 cm\\\\cos(38)= \frac{b}{20}\\0,8=\frac{b}{20}\\b= 16 cm\\\\b) sen(38)=\frac{10}{a}\\0,6=\frac{10}{a}\\a= \frac{10}{0,6}\\a= 16,66 cm\\\\cos(38)= \frac{b}{16,66}\\0,8=\frac{b}{16,66}\\b= 13,33 cm$