Question

Polinômios subtrair
A)(5×2-4×-7)-(3×2+7×+1)
B)(6×2-6×+9)-(3×2+8-2)
C)(7×-4y+2)-(2×-2y+5)
D)(4×-y-1)-(9×+y+3)
E)(-2a2-3°-+6)-(4a2-5°-+6)
F)(4×3-6×2+3×)-(7×3-6×2+8×)
G)(×2-5+3)-(4×2+6)
H)(×2+2×y+y2)-(y2+×2+2×y)
I)(7ab+4c-3a)-(5c+4a-10)
Uma ajudinha pfv

Answer 1

Resposta:

a) (5x²-4x+7)-(3x²+7x-1)=  

    5x²-4x+7-3x²-7x+1=

    5x²-3x²-4x-7x+7+1=

    2x²-11x+8

b) (6x²-6x+9)-(3x²+8x-2)=

    6x²-6x+9-3x²-8x+2=

    6x²-3x²-6x-8x+9+2=

    3x²-14x+11  

c) (7x-4y+2)-(2x-2y+5)=

    7x-4y+2-2x+2y-5=

    7x-2x-4y+2y+2-5=

    5x-2y-3

d) (4x-y-1)-(9x+y+3)=

    4x-y-1-9x-y-3=

    4x-9x-y-y-1-3=

    -5x-2y-4

e) (-2a²-3ª+6)-(-4a²-5ª+6)=

    -2a²-3a+6+4a²+5a-6=

    -2a²+4a²-3a+5a+6-6=

     2a²+2a

f) (4x³-6x²+3x)-(7x³-6x²+8x)=

    4x³-6x²+3x-7x³+6x²-8x=

    4x³-7x³-6x²+6x²+3x-8x=

    -3x³-5x

g) (x²-5x+3)-(4x²+6)=

     x²-5x+3-4x²-6=

     x²-4x²-5x+3-6=

      -3x²-5x-3

h) (x²+2xy+y²)-(y²+x²+2xy)=

    x²+2xy+y²-y²-x²-2xy=

    x²-x²+2xy-2xy+y²-y²=

                 0

i) (7ab+4c-3a)-(5c+4a-10)=

   7ab+4c-3a-5c-4a+10=

   7ab+4c-5c-3a-4a+10=

   7ab-c-7a+10

Explicação passo-a-passo: