Question

Poderiam me dar a área total e o volume destes 2 retângulos? agradeço gente, vocês são d+ <3

Answer 1

sendo a,b e c o comprimento,a largura e altura de um bloco retângular então

1)

$\mathsf{A_{total}=2.(ab+bc+ac)}$

2)

$\mathsf{V=a.b.c}$

a)

$\mathsf{A_{total}=2.((4{x}^{2}+1)(2{x}^{2}-2)+(2{x}^{2}-2)(3x+2)+(4{x}^{2}+1)(3x+2))}$

$\mathsf{A_{total}=2.(8{x}^{4}-6{x}^{2}-2+6{x}^{3}+4{x}^{2}-6x-4+12{x}^{3}+8{x}^{2}+3x+2)}$

$\mathsf{A_{total}=2.(8{x}^{4}+18{x}^{3}+6{x}^{2}-3x-4)=16{x}^{4}+36{x}^{3}+12{x}^{2}-6x-8}$

$\mathsf{V=(4{x}^{2}+1)(2{x}^{2}-2)(3x+2)=24{x}^{5}+16{x}^{4}-18{x}^{3}-12{x}^{2}-6x-4}$

b)

$\mathsf{A_{total}=2.((3{x}^{2}+5)(2{x}^{3}-2x)+(2{x}^{3}-2x)({x}^{2}+1)+(3{x}^{2}+5)({x}^{2}+1))}$

$\mathsf{A_{total}=16{x}^{5}+6{x}^{4}+8{x}^{3}+16{x}^{2}-24x+10}$

$\mathsf{V=(3{x}^{2}+5)(2{x}^{3}-2x)({x}^{2}+1)}$

$\mathsf{V=6{x}^{7}-2{x}^{5}-14{x}^{3}+10x}$