Question

poderiam me ajudar com essa questão? 8^2-x=(0,25)^x+1

Answer 1

$8^{2-x}=(0,25)^{x+1} \\ \\ (2^3)^{2-x}=(\frac{1}{4})^{x+1} \\ \\ 2^{2(2-x)}=(2^{-1})^{x+1} \\ \\ 2^{4-2x}=2^{-x-1} \\ \\ 4-2x=-x-1 \\ \\ x=5$

Answer 2

sendo [ 8 ]= 2^3 e [ 0,25 ] = 1/4 = 1/2^2 = 2^-1, logo:

[2]^3.(2-x) = [2]^-1.(x + 1)
3.(2x - x) = - 1.(x + 1)
6x - 3x = - x - 1
3x + x = - 1
4x = 1
x = 1/4