Question

Podem me ajudar Calculo Integral II !! 15 pontos+bonus

Answer 1

$\displaystyle\mathtt{A = \int\limits_{-1}^{2}({x}^{3}-2{x}^{2}-5x+6)dx}$

$\displaystyle\mathtt{A=\dfrac{1}{4}{x}^{4}-\dfrac{2}{3}{x}^{3}-\dfrac{5}{2}{x}^{2}+6x\big|_{-1}^{2}}$

$\mathtt{A=\dfrac{1}{4}.{2}^{4}-\dfrac{2}{3}.{2}^{3}-\dfrac{5}{2}.{2}^{2}+6.2}$

$\mathtt{4-\dfrac{16}{3}-10+12=6-\dfrac{16}{3}=\dfrac{18-16}{3}=\dfrac{2}{3}}$

$\mathtt{\dfrac{1}{4}{(-1)}^{4}-\dfrac{2}{3}{(-1)}^{3}-\dfrac{5}{2}.{(-1)}^{2}+6.(-1)}\\\mathtt{\dfrac{1}{4}+\dfrac{2}{3}-\dfrac{5}{2}-6}$

$\mathtt{\dfrac{3+8-30-72}{12}=-\dfrac{91}{12}}$

$\mathtt{A=\dfrac{2}{3}+\dfrac{91}{12}=\dfrac{8+91}{12}=\dfrac{99\div3}{12\div3}}$

$\mathtt{A=\dfrac{33}{4}}$

Esse gabarito está incorreto.

Answer 2

letra "a"

eu não tenho ABISOLUTA CERTEZA mas acho que é