Question

 pode me ajudar agradeço:D
 1)(O!=+1!)2! 

2)X-5=4!   B)N!/(n-1)=7  c)n!/n-1)!=7  
 c)n!/n-2)!    d)(n-1)/(n-3)!=0    
e)(x-2)!=24

Answer 1

$x-5 = 4!\\\\ 4! = 4*3*2*1 = 24\\\\ x-5 = 24\\\\ \boxed{x=29}$

$\frac{n!}{n-2!} = \frac{n*(n-1)(n-2)!}{(n-2)!} = \boxed{n^2-n}$

$(x-2)! = 24\\\\ 4! = 24\\\\ (x-2)! = 4!\\\\ x-2=4\\\\ \boxed{x=6}$

$\frac{n!}{(n-1)}=7 \\\\\ \frac{n(n-1)!}{(n-1)!} = 7\\\\ \boxed{n=7}$

$\frac{(n-1)!}{(n-3)!}=0\\\\\ \frac{(n-1)(n-2)(n-3)!}{(n-3)!} = 0\\\\\ n^2-3n+2 = 0\\\\\ \Delta = 1\\\\ x^1 = 2\\\\ x^2 = 1$