Question

please preciso da explicação abaixo da resposta porfa xD​

Answer 1

₃₆₉₁₄₇₂₅₈

a) log₂₇9=x

$9=27^{x}$

$3^{2}=3^{3x}$

$3x=2 <=>x=\frac{2}{3}$

b) logx64=3

$64=x^{3}$

$4^{3}=x^{3}$

$x=4$

c) log₇x=2

$x=7^{2}$

$x=49$

d) logx4=1/2

$4=x^{\frac{1}{2} }$

$4=\sqrt{x}$

$x=4^{2}=16$

e) log(1/3)3=x

$3=(\frac{1}{3} )^{x}$

$3=3^{-x}$

$-x=1$

$x=-1$

f) log 10=x

$10=10^{x}$

$x=1$