Question

pfv me ajudem..sou muito burra..

a) x - 40 = -- 4x

b) 2x - 5 = x + 4

c) 6(y - 5) = y

d) y + 2y + 12 = 54

e) 5(x - 9) - 3 = - 8 +x

f) 2y + 1 = 65

Answer 1

Resposta:

a)

$x - 40 = - 4 x \\ \\ x + 4x = 40 \\ \\ 5x = 40 \\ \\ x = \frac{40}{5} \\ \\ \pink{x = 8}$

b)

$2x - 5 = x + 4 \\ \\ 2x - x = 4 + 5 \\ \\ \pink{x = 9}$

c)

$6(y - 5) = y \\ \\ 6y - 30 = y \\ \\ 6y - y = 30 \\ \\ 5y = 30 \\ \\ y = \frac{30}{5} \\ \\ \pink{y = 6}$

d)

$y+ 2y + 12 = 54 \\ \\ 3y = 54 - 12 \\ \\ 3y = 42 \\ \\ y = \frac{42}{3} \\ \\ \pink{y = 14}$

e)

$5(x - 9) - 3 = - 8 + x \\ \\ 5x - 45 - 3 = - 8 + x \\ \\ 5x - 48 = - 8 + x \\ \\ 5x - x = - 8 + 48 \\ \\ 4x = 40 \\ \\ x = \frac{40}{4} \\ \\ \pink{x = 10}$

f)

$2y + 1 = 65 \\ \\ 2y = 65 - 1 \\ \\ 2y = 64 \\ \\ y = \frac{64}{2} \\ \\ \pink {y = 32}$

Bons Estudos!

Answer 2

a)

$x - 40 = - 4x$

$x + 4x = 40$

$5x = 40$

$x = \frac{40}{5}$

$x = 8$

b)

$2x - 5 = x + 4$

$2x - x = 4 + 5$

$x = 9$

c)

$6(y - 5) = y$

$6y - 30 = y$

$6y - y = 30$

$5y = 30$

$y = \frac{30}{5}$

$y = 6$

d)

$y + 2y + 12 = 54$

$y + 2y = 54 - 12$

$3y = 42$

$y = \frac{42}{3}$

$y = 14$

e)

$5(x - 9) - 3 = - 8 +x$

$5x - 45 - 3 = -8 + x$

$5x - x= -8 + 45 + 3$

$4x = 40$

$x = \frac{40}{4}$

$x = 10$

e)

$2y + 1 = 65$

$2y = 65 - 1$

$2y = 64$

$y = \frac{64}{2}$

$y = 32$