Question

pessoal me ajuda nesta atividade por favor ​

Answer 1

Letra A

$\frac{6^{2} }{3^{2} } + 4.10 -12=\\\\\\\frac{36}{9} +40 -12=\\4+40 -12=\\44-12=\\32$

Letra B

$(7^{2} -1):3 +2.5=\\(49-1):3 +10=\\48:3+10=\\16+10=\\26$

Letra C

$4^{2} -10+(2^{3}-5)=\\16-10+(8-5)=\\6+3=\\9$

Letra D

$5+3^{2}.2=\\5+9.2=\\5+18=\\23$

Letra E

$3^{2}:(4-1)+3.2^{2} =\\9:3+3.4=\\3+12=\\15$