Question

Pergunta esta na imagem!

Answer 1

Basta fazer:

a) t=0

$Q(0)=250.3^{\frac{0}{4}}=250.3^0=250.1=250 \ bacterias$

b)  t = 4

$Q(4)=250.3^{\frac{4}{4}}=250.3^1=250.3=750 \ bacterias$

c) t = 14

$Q(14)=250.3^{\frac{14}{4}}=250.3^{\frac{7}{2}}=250. \sqrt{2^7}=250. \sqrt{128}=250. 11,3=2.825$

Answer 2

Q(0) = 4 (aprox.)
Q(4) = 250 (aprox.)
Q(14) = 248092122 (aprox.)