Question

pelo amor de deus alguém me respondeeeeeeee
1-calcule os monomios :
a) 3x^2+5x^2-2x^2=
b) y^7+y^7-y^7=
c) (-7a^4)^2

2- considerando A=3x^2 e B= 6x^2
resolva:

a) a+b
b) b-a
c) A.B
d) b:a

Answer 1

As operações são realizadas a seguir.

• Resolvendo o problema

1 - calcule os monômios:

$a)\;3x^2+5x^2-2x^2=(3+5-2)x^2=(8-2)x^2=6x^2\\\\\\b)\;y^7+y^7-y^7=(1+1-1)y^7=(2-1)y^7=y^7\\\\\\c)\;(-7a^4)^2=(-7)^2\;.\;(a^4)^2=49\;.\;a^8=49a^8$

2 - considerando $A=3x^2$ e $B=6x^2$ resolva:

$a)\;A+B=3x^2+6x^2=(3+6)x^2=9x^2\\\\\\b)\;B-A=6x^2-3x^2=(6-3)x^2=3x^2\\\\\\c)\;A.B=3x^2\;.\;6x^2=(3\;.\;6)\;.\;(x^2\;.\;x^2)=18\;.\;x^4=18x^4\\\\\\d)\;B:A=\dfrac{6x^2}{3x^2}=\dfrac{6}{3}\;.\;\dfrac{x^2}{x^2}=2\;.\;1=2$

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