Question

Para quais valores de S os pontos (6, S), (3,4) e (2-S, 2) são colineares?

Answer 1

A = (6,S)

B = (3,4)

C = (2-S, 2)

y = ax + b

a = s - 4 / 6 - 3 = s-4/2

y - 4 = (s-4)/2(x - 3)

Aplicarei C.

2 - 4 = (s-4)/2(2 - s - 3)

-2 = -(s-4)/2(s+1)

4 = (s - 4)(s + 1)

s² -3s -4 = 4

s² -3s -8 = 0

s = -3/2 +- /9 + 32 /2 = -3/2 +- /41 /2