Question

• Para quais valores de p é verdadeira a igualdade:

$\frac{3 \times {2}^{2} - ( {3}^{ - 2} ) + (0.2) }{ {p}^{2} } = 8$
(*Boiando*, Help please;-;)​

Answer 1

Resposta:

$\frac{3 \times {2}^{2} - ( {3}^{ - 2} ) + (0,2) }{ {p}^{2} } = 8 \\ 8 {p}^{2} = 3 \times 4 - \frac{1}{ {3}^{2} } + 0,2 \\ 8 {p}^{2} = 12 - \frac{1}{9} + \frac{1}{5} \\ 8 {p}^{2} = \frac{540 - 5 + 9}{45} \\ 8 {p}^{2} = \frac{544}{45} \\ 8 {p}^{2} .45 = 544 \\ 45 {p}^{2} = 68 \\ {p}^{2} = \frac{68}{45} \\ p = \pm\sqrt{ \frac{68}{45} } \\ p = \pm \frac{2 \sqrt{17} }{3 \sqrt{5} } \\ p = \pm \frac{2}{3} \sqrt{ \frac{17}{5} }$