Question

para multiplicar um inteiro por fração, multiplica-se o inteiro pelo numerador e conserva-se o mesmo denominador.​

Answer 1

Resposta e explicação passo a passo:

$a)\ \frac{15}{8}\\\\b)\ \frac{72}{12}=6\\\\c)\ \frac{12}{5}\\\\d)\ \frac{39}{6}=\frac{13}{2}\\\\e)\ \frac{36}{7}\\\\f)\ \frac{36}{3}=12\\\\g)\ \frac{21}{9}=\frac{7}{3}\\\\h)\ \frac{45}{4}$

Answer 2

Explicação passo-a-passo:

$a)3 \times \frac{5}{8} = \frac{3 \times 5}{8} = \frac{15}{8}$

$b)8 \times \frac{9}{12} = \frac{72}{12} = 6$

$c)4 \times \frac{3}{5} = \frac{4 \times 3}{1 \times 5} = \frac{12}{5}$

$d)12 \times \frac{3}{7} = \frac{12 \times 3}{1 \times 7} = \frac{36}{7}$

$e)13 \times \frac{3}{6} = \frac{13 \times 3}{1 \times 6} = \frac{39}{6} = \div \frac{3}{3} = \frac{13}{2}$

$f)9 \times \frac{4}{3} = \frac{9 \times 4}{1 \times 3} = \frac{36}{3} = 12$

$g)7 \times \frac{3}{9} = \frac{7 \times 3}{1 \times 9} = \frac{21}{9} = \div \frac{3}{3} = \frac{7}{3}$

$h)15 \times \frac{3}{4} = \frac{15 \times 3}{1 \times 4} = \frac{45}{4}$