para a função y = cos (x2 2x-1) -3 sen x marque a alternativa que mostra a derivada desta função
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lembrando que a derivada de cos(u) = -sen(u)*u'
(u)' é a derivada do que esta dentro do cosseno
![y=cos(x^2+2x-1)-3sen(x)\\\\y'=-sen(x^2+2x-1)*(x^2+2x-1)' -3*cos(x)\\\\y'=-sen(x^2+2x-1)*(2x^{2-1}+2x^{1-1}-0) -3*cos(x)\\\\y'=-sen(x^2+2x-1)*(2x+2)-3cos(x)\\\\\boxed{\boxed{y'=- [2(x+1)*sen(x^2+2x-1)+3cos(x)]}}](https://tex.z-dn.net/?f=y%3Dcos%28x%5E2%2B2x-1%29-3sen%28x%29%5C%5C%5C%5Cy%27%3D-sen%28x%5E2%2B2x-1%29%2A%28x%5E2%2B2x-1%29%27+-3%2Acos%28x%29%5C%5C%5C%5Cy%27%3D-sen%28x%5E2%2B2x-1%29%2A%282x%5E%7B2-1%7D%2B2x%5E%7B1-1%7D-0%29+-3%2Acos%28x%29%5C%5C%5C%5Cy%27%3D-sen%28x%5E2%2B2x-1%29%2A%282x%2B2%29-3cos%28x%29%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7By%27%3D-+%5B2%28x%2B1%29%2Asen%28x%5E2%2B2x-1%29%2B3cos%28x%29%5D%7D%7D "y=cos(x^2+2x-1)-3sen(x)\\\\y'=-sen(x^2+2x-1)*(x^2+2x-1)' -3*cos(x)\\\\y'=-sen(x^2+2x-1)*(2x^{2-1}+2x^{1-1}-0) -3*cos(x)\\\\y'=-sen(x^2+2x-1)*(2x+2)-3cos(x)\\\\\boxed{\boxed{y'=- [2(x+1)*sen(x^2+2x-1)+3cos(x)]}}")
(u)' é a derivada do que esta dentro do cosseno
patnassinger:
y'=(-2x - 2).sen (x^2 + 2x -1 ) -3 cos (x)
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b) y’ = (-2x-2).sen(x2 +2x-1)-3 cos (x).
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