Question

p(x)=x.(x-3).(x+2)
quais as raízes desse polinômios ❤
✌ajudinha!
ass:*******​

Answer 1

Explicação passo-a-passo:

x × (x - 3) × (x + 2) = 0

(x² - 3x) × (x + 2) = 0

x³ + 2x² - 3x² - 6x = 0

x³ - x² - 6x = 0

x(x² - x - 6) = 0

$x = \frac{ - ( - 1) + - \sqrt{ {( - 1)}^{2} - 4 \times 1 \times ( - 6)} }{2 \times 1} \\ \\ x = \frac{1 + - \sqrt{1 + 24} }{2} \\ \\ x = \frac{1 + - \sqrt{25} }{2} \\ \\ x1 = \frac{1 + 5}{2} = \frac{6}{2} = 3 \\ \\ x2 = \frac{1 - 5}{2} = \frac{ - 4}{2} = - 2 \\ \\ x3 = 0$