Question

P.A:(5,9,13...).qual será o 102º termo ?

Answer 1

$a_{n} = a_{102}= ?; a_{1} =5;n=102;r=4\\ \\ a_{n} = a_{1} +(n-1).r \\\\ a_{102}=5+(102-1).4\to a_{102}=5+101.4\to a_{102}=5+404\to\\ a_{102}=409$