Matemática, perguntado por alic157, 9 meses atrás

operação com radicais para efetuar a adição algébrica com radicais simplificamos os radicais e reduza os termos que tem radicais iguais somando algebricamente os fatores externos calcule:​

Anexos:

Soluções para a tarefa

Respondido por CyberKirito
12

1)

a)

\boxed{\boxed{\mathsf{\sqrt{49}+\sqrt{16}=7+4=11}}}

b)

\boxed{\boxed{\mathsf{\sqrt[3]{8}-\sqrt[4]{16}=2-2=0}}}

c)

\boxed{\boxed{\mathsf{-5\sqrt{9}+2\sqrt{169}=-5.3+2.13=-15+26=11}}}

d)

\boxed{\boxed{\mathsf{10\sqrt[3]{2}+4\sqrt[3]{2}-\sqrt[3]{2}=13\sqrt[3]{2}}}}

e)

\boxed{\boxed{\mathsf{\sqrt{18}+2\sqrt{50}=3\sqrt{2}+10\sqrt{2}=13\sqrt{2}}}}

f)

\boxed{\boxed{\mathsf{\sqrt{25}+\sqrt[3]{27}+\sqrt[4]{81}=5+3+3=11}}}

g)

\boxed{\boxed{\mathsf{\sqrt{64}+\sqrt[3]{-64}+\sqrt[6]{64}=8-4+2=6}}}

2)

a)

\boxed{\boxed{\mathsf{3\sqrt{5}+\sqrt{5}-6\sqrt{5}=-2\sqrt{5}}}}

b)

\boxed{\boxed{\mathsf{5\sqrt[5]{3}+2\sqrt[5]{3}-2\sqrt[5]{3}+\sqrt[5]{3}=6\sqrt[5]{3}}}}

c)

\boxed{\boxed{\mathsf{-4+\sqrt[3]{5}+2\sqrt[3]{5}-4=3\sqrt[3]{5}-8}}}

d)

\boxed{\boxed{\mathsf{2\sqrt[5]{3}-2\sqrt{3}+3\sqrt{3}+3\sqrt[5]{3}=5\sqrt[5]{3}+\sqrt{3}}}}

e)

\boxed{\boxed{\mathsf{\sqrt{50}+\sqrt{18}-\sqrt{8}=5\sqrt{2}+3\sqrt{2}-2\sqrt{2}=6\sqrt{2}}}}

f)

\boxed{\boxed{\mathsf{2\sqrt{27}-5\sqrt{12}=6\sqrt{3}-10\sqrt{3}=-4\sqrt{3}}}}

g)

\boxed{\boxed{\mathsf{4\sqrt{63}-\sqrt{7}=12\sqrt{7}-\sqrt{7}=11\sqrt{7}}}}

h)

\boxed{\boxed{\mathsf{\sqrt{12}+\sqrt{75}+\sqrt{108}=2\sqrt{3}+5\sqrt{3}+6\sqrt{3}=13\sqrt{3}}}}


alic157: obrigada aaaaaaaaaaa
alic157: \(◎o◎)/\(◎o◎)/\(◎o◎)/\(◎o◎)/
CyberKirito: De nada
alic157: me salvou
CyberKirito: Mais legal que isso
CyberKirito: Só trigonometria
alic157: hahahahah
alic157: morta
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