Question

Obtenha as coordenadas do ponto Q que divide o segmento de extremos P(-3,5)e R(1,3) na proporção PQ/QR= 2/5

Answer 1

$\frac{PQ}{QR} = \frac{xQ-xP}{xR-xQ} = \frac{2}{5} \\ \frac{xQ+3}{1-xQ} = \frac{2}{5} =\ \textgreater \ 5xQ+15=2-2xQ=\ \textgreater \ 7xQ=-13=\ \textgreater \ xQ=- \frac{13}{7} \\ \frac{yQ-yP}{yR-yQ}= \frac{2}{5} =\ \textgreater \ \frac{yQ-5}{3-yQ} = \frac{2}{5} =\ \textgreater \ 5yQ-25=6-2yQ=\ \textgreater \ 7yQ=31 \\ yQ= \frac{31}{7} =\ \textgreater \ Q(- \frac{13}{7}, \frac{31}{7} )$