Question

Observe atentamente a figura abaixo: *



O valor da incógnita x é?

x=19

x=36

x=12

x=26

x=30

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Answer 1

$\Large\boxed{\begin{array}{l}\underline{\rm Observe~a~figura~que~eu~anexei.}\\\underline{\rm C\acute alculo~da~medida~y:}\\\sf tg(60^\circ)=\dfrac{y}{12}\\\sf \sqrt{3}=\dfrac{y}{12}\\\sf y=12\sqrt{3}\\\underline{\rm C\acute alculo~da~medida~x:}\\\sf tg(30^\circ)=\dfrac{y}{x}\\\sf\dfrac{\diagdown\!\!\!\!\!\sqrt{3}}{3}=\dfrac{12\diagdown\!\!\!\!\!\sqrt{3}}{x}\\\sf x=3\cdot12\\\sf x=36\end{array}}$

Answer 2

• Segui abaixo a resolução:

$tg60 = \frac{cat.oposto}{cat.adjascente} \\ \\ \ \sqrt{3} = \frac{y}{12} \\ \\ y= 12 \sqrt{3}$

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$tg30 = \frac{12 \sqrt{3} }{x} \\ \\ \frac{ \sqrt{3} }{3} = \frac{12 \sqrt{3} }{x} \\ \\ \sqrt{3} x = 36 \sqrt{3} \\ \\ x = \frac{36 \sqrt{3} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ x = \frac{36 \times \sqrt{9} }{ \sqrt{9} } \\ \\ x = \frac{36 \times 3}{3} \\ \\ \red{\boxed{\sf \ \red{x = 36}}}$

espero ter ajudado!