Observando os resultados obtidos no exercício anterior respondam:para essas matrizes ,A e B,vale a igualdade (A+B)(A-B)=A2-B2?
Soluções para a tarefa
(A+B)(A-B) =
A+B = \left[\begin{array}{ccc}2&3\\5&1\\\end{array}\right] + \left[\begin{array}{ccc}3&1\\2&1\\\end{array}\right] = \left[\begin{array}{ccc}5&4\\7&2\\\end{array}\right]
A-B = \left[\begin{array}{ccc}2&3\\5&1\\\end{array}\right] - \left[\begin{array}{ccc}3&1\\2&1\\\end{array}\right] = \left[\begin{array}{ccc}-1&2\\3&0\\\end{array}\right]
A2 = \left[\begin{array}{ccc}2&3\\5&1\\\end{array}\right] \left[\begin{array}{ccc}2&3\\5&1\\\end{array}\right] = \left[\begin{array}{ccc}19&9\\15&16\\\end{array}\right]
B2 = \left[\begin{array}{ccc}3&1\\2&1\\\end{array}\right] \left[\begin{array}{ccc}3&1\\2&1\\\end{array}\right] = \left[\begin{array}{ccc}11&4\\8&3\\\end{array}\right]
Eu não vpu fazer A2 - B2 aqui, porem os resultados são diferentes, então não