Question

O volume do sólido limitado pelos planos x=0, x=4, y=0, y=2, z=0 e z= 5-x/2 é?

Answer 1

$\int\limits^{2}_{0} \int\limits^{4}_{0} \int\limits^{ \frac{5-x}{2} }_{0}dzdxdy \\\\= \int\limits^{2}_{0} \int\limits^{4}_{0} \frac{5-x}{2} dxdy \\\\ = \int\limits^{2}_{0}dy * \int\limits^{4}_{0} ( \frac{5}{2}- \frac{x}{2})dx \\\\ = [y]^2_0 *[ \frac{5x}{2}- \frac{x^2}{4} ]^4_0\\\\ = [2]*[10-4]= 12$

Answer 2

A ALTERNATIVA CORRETA  É : 32