Question

O volume de H20 formado nas CNTP, quando forem utilizados 10 mol de C8H18 é?

Answer 1

 C8H18(l)+ 25/2 O2(g) -> 8 CO2(g)+ 9H2O(v)

1 mol de C8H18 --- 9 mols de H2O
10 mols de C8H18 --- x
x = 90 mols de H2O

1 mol --- 22,4L
90 mols -- x
x = 2016L