Question

O vértice da parábola y = 2xao quadrado - 6x +4​

Answer 1

Oi

Primeiro calculamos o delta ...

2x² - 6x + 4 = 0

Δ = 36 - 32

Δ = 4

agora o x vértice e o y vértice

Xv = -b/2a

Xv = 6/2.2

Xv = 6/4

Xv = 3/2

Yv = -Δ/4a

Yv = -4/4.2

Yv = -4/8

Yv = - 1/2

Vértice = (3/2 , - 1/2)  

Bons estudos! :)

Answer 2

$2 {x}^{2} - 6x + 4 \\ xv = - \frac{( - 6)}{2.2} = \frac{6}{4} = \frac{3}{2}$

$Δ =36 - 32 = 4 \\ yv = - \frac{Δ}{4a} \\ yv = - \frac{4}{4.2} = - \frac{1}{2}$

$v = (xv,yv) \\ v = ( \frac{3}{2} , - \frac{1}{2} )$