Question

O vértice da função g(x) = x² - 4x + 4 se localiza no ponto: *
(-2,0)
(2,0)
(2,2)
(2,-2)

Answer 1

Yv = - delta/4a

Yv = - (16 - 16)/4

Yv = 0/4

Yv = 0

Xv = - b/2a

Xv = - (- 4)/2

Xv = 4/2

Xv = 2

Resposta: (2,0)

Answer 2

Explicação passo-a-passo:

As coordenadas do vértice são dadas por:

• $\sf x_V=\dfrac{-b}{2a}$

• $\sf y_V=\dfrac{-\Delta}{4a}$

Temos:

$\sf x_V=\dfrac{-b}{2a}$

$\sf x_V=\dfrac{-(-4)}{2\cdot1}$

$\sf x_V=\dfrac{4}{2}$

$\sf \red{x_V=2}$

• $\sf \Delta=(-4)^2-4\cdot1\cdot4$

$\sf \Delta=16-16$

$\sf \Delta=0$

$\sf y_V=\dfrac{-\Delta}{4a}$

$\sf y_V=\dfrac{-0}{4\cdot1}$

$\sf y_V=\dfrac{0}{4}$

$\sf \red{y_V=0}$

O vértice é V(2, 0)