Question

O valor do determinante
321
132
010

Answer 1

Resposta:

$\left[\begin{array}{ccc}3&2&1\\1&3&2\\0&1&0\end{array}\right] =3.3.0+2.2.0+1.1.1-(0.3.1+1.2.3+1.2.0)$

= $0+0+1-(0+6+0)$

= $1-6$

= $-5$

det = -5

bons estudos!