Question

O valor delta na equação -x^2 -4x +5=o é.

Answer 1

Resposta:

x^2 -4x +5 ------> (x-(2-i)) x(x-(2+i))

Answer 2

$\Large\boxed{\begin{array}{l}\sf -x^2-4x+5=0\\\begin{cases}\sf a=-1\\\sf b=-4\\\sf c=5\end{cases}\\\sf\Delta=b^2-4ac\\\sf\Delta=(-4)^2-4\cdot(-1)\cdot5\\\sf\Delta=16+20\\\huge\boxed{\boxed{\boxed{\boxed{\sf\Delta=36}}}}\end{array}}$