Question

o valor de x para q a equação seja 11x-5(98/5+11x/5)=0 ​

Answer 1

o nosso famoso a,b e c

a) 11

b)-5

c)11

∆=b²-4ac

∆=-5²-4.11.11

∆=10-4.11.11

∆=10-44.11

∆=10-484

∆=474

formula de Bhaskara

$\frac{x = - b + - \sqrt{d} }{2.a}$

x=5+-√474

___________

2.11

x=5+21,771..

____________

2.11

26,771..

___________

2.11

$\frac{26.711}{22} = 1.214$

ou

$\frac{x = 5 - 21.711}{2 \times 11} \\ \\ \frac{x = 16.711}{22 } \\ \\ x = 0.759..$

{0,759 e 1,214}