Question

o valor de lim x → -∞ 3x+2/x^2-5x+6

Answer 1

$\lim_{x \to \infty} \frac{3x+2}{x^2-5x+6}= \lim_{x \to \infty} \frac{ \frac{3x}{x^2} + \frac{2}{x^2} }{ \frac{x^2}{x^2}- \frac{5x}{x^2}+ \frac{6}{x^2}}= \lim_{x \to \infty} \frac{ \frac{3}{x} + \frac{2}{x^2} }{ 1- \frac{5}{x}+ \frac{6}{x^2}}= \frac{ \frac{3}{\infty} + \frac{2}{\infty^2} }{ 1- \frac{5}{\infty}+ \frac{6}{\infty ^2}}= \frac{0+0}{1-0+0}= \frac{0}{1} =0$

Answer 2

RESPOSTA CORRETA : 0