Question

O valor de [2+0+0+9_(2×0×0+9)]÷[2×2×2+3×3-2×3]=

Answer 1

[2+0+0+9_(2×0×0+9)]÷[2×2×2+3×3-2×3]=
[2+0+0+9-(+9)]÷[8+9-6]
[2+9-9]÷[8+9-6]
2÷11
2/11