Question

O valor da expressão $\frac{1}{2} ^{2} + \frac{1}{4}^{2}.2 -^{2}+16 ^{0}$

Answer 1

$(\frac{1}{2})^2+(\frac{1}{4})^2.2^{-2}+16^0=\\ \\ \frac{1}{4}+\frac{1}{16}.\frac{1}{4}+1\\ \\ \frac{1}{4}+\frac{1}{64}+1=\frac{81}{64}$

Answer 2

$(\frac{1}{2} )^{2} + (\frac{1}{4} )^{2} *2^{-2} + 16^{0} = \\\\ \frac{1}{4} + \frac{1}{16} * \frac{1}{4} + 1 =\\\\ \frac{1}{4} + \frac{1}{64} + 1 =\\\\ \frac{16 + 1 + 64}{64} = \frac{81}{64} \to \boxed{\frac{81}{64} }$