Question

O valor da expressão é: *

a) 8

b) 1

c) 4

d) 2​

Answer 1

Siga a resolução abaixo

$\mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} + {( - 1)}^{5} + {10}^{0} }{ {1}^{50} \times {2}^{ - 1} \times {16}^{ \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} - 1 + {10}^{0} }{ {1}^{50} \times {2}^{ - 1} \times {16}^{ \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} - 1 + 1 }{ {1}^{50} \times {2}^{ - 1} \times {16}^{ \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} - 1 + 1 }{1 \times {2}^{ - 1} \times {16}^{ \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} - 1 + 1}{1 \times {2}^{ - 1} \times { {(2}^{4}) }^{ \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} - 1 + 1}{1 \times {2}^{ - 1} \times {2}^{4 \times \frac{1}{2} } } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} -1 + 1}{1 \times {2}^{ - 1} \times {2}^{2} } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} \cancel{ - 1} \cancel{ + 1}}{\cancel{1} \times {2}^{ - 1} \times {2}^{2} } } \\ \\ \mathtt{ \frac{ {2}^{ - 1} \times {2}^{4} }{ {2}^{ - 1} \times {2}^{2} } } \\ \\ \mathtt{ \frac{ {2}^{ - 1+ 4} }{ {2}^{ - 1} \times {2}^{2} } } \\ \\ \mathtt{ \frac{ {2}^{3} }{ {2}^{ - 1} \times {2}^{2} } } \\ \\ \mathtt{\mathtt{ \frac{ {2}^{3} }{ {2}^{ - 1 + 2} } }} \\ \\ \mathtt{ \frac{ {2}^{3} }{ {2}^{1} } } \\ \\ \mathtt{ \frac{2 \times 2 \times 2}{2} } \\ \\ \mathtt{ \frac{\cancel{2} \times 2 \times 2}{\cancel{2}} } \\ \\ \mathtt{2 \times 2} \\ \\ \boxed{\mathtt{4}}$

Resposta: item (c).

Att: José Armando